# Solutions

Get detailed explanations to advanced GMAT questions.

### Question

Kay began a certain game with x chips. On each of the next two plays, she lost one more than half the number of chips she had at the beginning of that play. If she had 5 chips remaining after her two plays, then x is in the interval:

Option A:

7<x<12

Option B:

13<x<18

Option C:

19<x<24

Option D:

25<x<30

Option E:

31<x<35

### Difficulty Level

Hard### Solution

Option D is the correct answer.

### Option Analysis

On the first play she lost (x/2)+1 chips and she was left with x−((x/2)+1)=(x−2)/2 chips.

On the second play she lost ((x−2)/4)+1 chips.

So, we have that x−((x/2)+1)−((x−2)/4)+1))=5 –> x=26.

### Related Questions

- If (2^x) (2^y) = 8 and (9^x)(3^y) = 81, then (x,y) equals:

- If v = √(2(9.8))m/0.5j), m = 96, and j = 49,which of the following most closely approximates the value of v?

- 6.2 is what percent of 1000?

- During an experiment, the temperature of a liquid was measured several times. The temperatures, in degree…

- The outside of the rectangular box represented in the figure above is to be decorated by attaching pieces of…