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Kay began a certain game with x chips. On each of the next two plays, she lost one more than half the number of chips she had at the beginning of that play. If she had 5 chips remaining after her two plays, then x is in the interval:

Option A:

7<x<12

Option B:

13<x<18

Option C:

19<x<24

Option D:

25<x<30

Option E:

31<x<35

Option D is the correct answer.

On the first play she lost (x/2)+1 chips and she was left with x−((x/2)+1)=(x−2)/2 chips.

On the second play she lost ((x−2)/4)+1 chips.

So, we have that x−((x/2)+1)−((x−2)/4)+1))=5 –> x=26.

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